Sagun

Any idea why this is not working?

i also tried:

$query = "select * from tblMail where mFrom = '". $_COOKIE['userEmail'] ."' ";
$result = mysql_querry($query, $connection);


Error msg:

Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource on Line 36
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource on Line 43

It's something to do with @ i believe..

thanks in advance..